A window washer pulls a rubber squeegee down a very tall vertical window. The squeegee has mass m = g and is mounted on the end of a light rod. The coefficient of kinetic friction between the squeegee and the dry glass is u = . The window washer presses it against the window with a force having a horizontal component of n = N.
(a) If she pulls the squeegee down the window at constant velocity, what vertical force component must she exert?
(b) The window washer increases the downward force component by 25.0%, while all other forces remain the same. Find the squeegee's acceleration in this situation.
(c) The squeegee is moved into a wet portion of the window, where its motion is resisted by a fluid drag force R proportional to its velocity according to R = 220.0v, where R is in newtons and v is in meters per second. Find the terminal velocity that the squeegee approaches, assuming the window washer exerts the same force described in part (b)
b =
fk =